# Distance from Pathankot Air Force Station (IXP) to Port Louis (MRU)

> 6,159 km · estimated flight time 8h · Long-haul route.

## Summary

- **Distance**: 6,159 km / 3,827 mi / 3,326 nm
- **Estimated flight time**: 8h
- **Heading**: 201° (south southwest)
- **Return heading**: 18° (north northeast)
- **Classification**: Long-haul
- **Type**: International (India) → Mauritius
- **Intercontinental**: Asia → Africa
- **Time difference**: -1.5h (When it's 15:57 in Pathankot Air Force Station, it's 14:27 in Port Louis)
- **Elevation difference**: 831 ft (MRU is lower than IXP)

## Airports

### [Pathankot Air Force Station (IXP)](https://www.flightduration.online/airport/ixp-pathankot-air-force-station/1ef266df-f246-65b0-a1c9-06bb2780ed98)

- City: Pathankot Air Force Station, India
- ICAO: VIPK
- Timezone: Asia/Kolkata
- Coordinates: 32.230000, 75.630000
- Elevation: 1,017 ft

### [Sir Seewoosagur Ramgoolam International Airport (MRU)](https://www.flightduration.online/airport/mru-port-louis-sir-seewoosagur-ramgoolam-international-airport/1ef266de-d896-635a-a611-06bb2780ed98)

- City: Port Louis, Mauritius
- ICAO: FIMP
- Timezone: Indian/Mauritius
- Coordinates: -20.430000, 57.680000
- Elevation: 186 ft

## Route notes

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

Time-zone information: When it's 15:57 in Pathankot Air Force Station, it's 14:27 in Port Louis.

## Related

- [Pathankot Air Force Station (IXP)](https://www.flightduration.online/airport/ixp-pathankot-air-force-station/1ef266df-f246-65b0-a1c9-06bb2780ed98)
- [Sir Seewoosagur Ramgoolam International Airport (MRU)](https://www.flightduration.online/airport/mru-port-louis-sir-seewoosagur-ramgoolam-international-airport/1ef266de-d896-635a-a611-06bb2780ed98)
- [Flight duration calculator](/#calculator)