The flight distance from Amsterdam Airport Schiphol (AMS) in Amsterdam, Netherlands to Sandy Lake Airport (ZSJ) in Sandy Lake, Canada is 6,060 kilometers (3,766 miles / 3,272 nautical miles). The estimated flight time for this route is approximately 8h, flying northwest at a heading of 313°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting Netherlands with Canada. It is an intercontinental flight between Europe and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 21:59 in Amsterdam, it's 14:59 in Sandy Lake. With a 7-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

The return flight from Sandy Lake (ZSJ) to Amsterdam (AMS) follows a heading of 48° (northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Amsterdam Airport Schiphol (AMS) and Sandy Lake Airport (ZSJ) detail pages, or use our flight duration calculator to compare other routes.