The flight distance from Eleftherios Venizelos International Airport (ATH) in Athens, Greece to Comayagua-Palmerola International Airport (XPL) in Comayagua, Honduras is 10,826 kilometers (6,727 miles / 5,845 nautical miles). The estimated flight time for this route is approximately 14h, flying west northwest at a heading of 295°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting Greece with Honduras. It is an intercontinental flight between Europe and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 22:48 in Athens, it's 14:48 in Comayagua. With a 8-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,756 feet between the two airports. Comayagua-Palmerola International Airport sits higher than Eleftherios Venizelos International Airport.

The return flight from Comayagua (XPL) to Athens (ATH) follows a heading of 48° (northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Eleftherios Venizelos International Airport (ATH) and Comayagua-Palmerola International Airport (XPL) detail pages, or use our flight duration calculator to compare other routes.