CCU
Kolkata
India
4,924 km
3,060 miles
DES
Desroches Island
Seychelles
Distance
4,924 km
3,060 mi / 2,659 nm
Est. Flight Time
7h
Long-haul route
Time Difference
-1.5h
Asia/Kolkata
Heading
234°
southwest

Airport Comparison

CCU DES
Airport Name Netaji Subhash Chandra Bose International Airport Desroches Airport
IATA Code CCU DES
ICAO Code VECC FSDR
City Kolkata Desroches Island
Country India Seychelles
Timezone Asia/Kolkata Indian/Mahe
Elevation 16 ft 10 ft
Coordinates 22.650000, 88.450000 -5.700000, 53.660000

Kolkata (CCU) to Desroches Island (DES) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Desroches Airport (DES) in Desroches Island, Seychelles is 4,924 kilometers (3,060 miles / 2,659 nautical miles). The estimated flight time for this route is approximately 7h, flying southwest at a heading of 234°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with Seychelles. It is an intercontinental flight between Asia and Africa. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 01:50 in Kolkata, it's 00:20 in Desroches Island.

The return flight from Desroches Island (DES) to Kolkata (CCU) follows a heading of 49° (northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Desroches Airport (DES) detail pages, or use our flight duration calculator to compare other routes.

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