CCU
Kolkata
India
4,126 km
2,564 miles
DSO
Sondok Airport
KP
Distance
4,126 km
2,564 mi / 2,228 nm
Est. Flight Time
6h
Long-haul route
Time Difference
+3.5h
Asia/Kolkata
Heading
53°
northeast

Airport Comparison

CCU DSO
Airport Name Netaji Subhash Chandra Bose International Airport Sondok Airport
IATA Code CCU DSO
ICAO Code VECC ZKSD
City Kolkata N/A
Country India KP
Timezone Asia/Kolkata Asia/Pyongyang
Elevation 16 ft 12 ft
Coordinates 22.650000, 88.450000 39.750000, 127.470000

Kolkata (CCU) to Sondok Airport (DSO) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Sondok Airport (DSO) in Sondok Airport, KP is 4,126 kilometers (2,564 miles / 2,228 nautical miles). The estimated flight time for this route is approximately 6h, flying northeast at a heading of 53°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with KP. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 20:51 in Kolkata, it's 00:21 in Sondok Airport. The 3.5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

The return flight from Sondok Airport (DSO) to Kolkata (CCU) follows a heading of 254° (west southwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Sondok Airport (DSO) detail pages, or use our flight duration calculator to compare other routes.

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