The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Lbj Ranch Airport (JCY) in Johnson City, United States is 14,085 kilometers (8,752 miles / 7,605 nautical miles). The estimated flight time for this route is approximately 18h, flying north at a heading of 8°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with United States. It is an intercontinental flight between Asia and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 05:15 in Kolkata, it's 17:45 in Johnson City. With a 11.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,499 feet between the two airports. Lbj Ranch Airport sits higher than Netaji Subhash Chandra Bose International Airport.

The return flight from Johnson City (JCY) to Kolkata (CCU) follows a heading of 352° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Lbj Ranch Airport (JCY) detail pages, or use our flight duration calculator to compare other routes.