The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to San Cristobal Airport (SCY) in San Cristobal, Ecuador is 17,589 kilometers (10,929 miles / 9,497 nautical miles). The estimated flight time for this route is approximately 22h, flying north at a heading of 355°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with Ecuador. It is an intercontinental flight between Asia and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 04:15 in Kolkata, it's 16:45 in San Cristobal. With a 11.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

The return flight from San Cristobal (SCY) to Kolkata (CCU) follows a heading of 5° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and San Cristobal Airport (SCY) detail pages, or use our flight duration calculator to compare other routes.