CCU
Kolkata
India
4,080 km
2,535 miles
TAC
Tacloban City
Philippines
Distance
4,080 km
2,535 mi / 2,203 nm
Est. Flight Time
6h
Long-haul route
Time Difference
+2.5h
Asia/Kolkata
Heading
102°
east southeast

Airport Comparison

CCU TAC
Airport Name Netaji Subhash Chandra Bose International Airport Daniel Z. Romualdez Airport
IATA Code CCU TAC
ICAO Code VECC RPVA
City Kolkata Tacloban City
Country India Philippines
Timezone Asia/Kolkata Asia/Manila
Elevation 16 ft 10 ft
Coordinates 22.650000, 88.450000 11.230000, 125.030000

Kolkata (CCU) to Tacloban City (TAC) Flight Distance

The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Daniel Z. Romualdez Airport (TAC) in Tacloban City, Philippines is 4,080 kilometers (2,535 miles / 2,203 nautical miles). The estimated flight time for this route is approximately 6h, flying east southeast at a heading of 102°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting India with Philippines. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 03:16 in Kolkata, it's 05:46 in Tacloban City.

The return flight from Tacloban City (TAC) to Kolkata (CCU) follows a heading of 293° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Daniel Z. Romualdez Airport (TAC) detail pages, or use our flight duration calculator to compare other routes.

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