The flight distance from Netaji Subhash Chandra Bose International Airport (CCU) in Kolkata, India to Taisha Airport (TSC) in Taisha, Ecuador is 17,299 kilometers (10,749 miles / 9,341 nautical miles). The estimated flight time for this route is approximately 21h, flying northwest at a heading of 324°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting India with Ecuador. It is an intercontinental flight between Asia and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 18:04 in Kolkata, it's 07:34 in Taisha. With a 10.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,653 feet between the two airports. Taisha Airport sits higher than Netaji Subhash Chandra Bose International Airport.

The return flight from Taisha (TSC) to Kolkata (CCU) follows a heading of 33° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Netaji Subhash Chandra Bose International Airport (CCU) and Taisha Airport (TSC) detail pages, or use our flight duration calculator to compare other routes.