The flight distance from Charlotte/Douglas International Airport (CLT) in Charlotte, United States to Kalymnos Airport (JKL) in Kalymnos Island, Greece is 9,073 kilometers (5,638 miles / 4,899 nautical miles). The estimated flight time for this route is approximately 12h, flying northeast at a heading of 50°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting United States with Greece. It is an intercontinental flight between North America and Europe. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 05:55 in Charlotte, it's 12:55 in Kalymnos Island. With a 7-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

The return flight from Kalymnos Island (JKL) to Charlotte (CLT) follows a heading of 308° (northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Charlotte/Douglas International Airport (CLT) and Kalymnos Airport (JKL) detail pages, or use our flight duration calculator to compare other routes.