The flight distance from Cooperstown-Westville Airport (COP) in Cooperstown, United States to O. R. Tambo International Airport (JNB) in Johannesburg, South Africa is 12,969 kilometers (8,059 miles / 7,003 nautical miles). The estimated flight time for this route is approximately 16h, flying east southeast at a heading of 102°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting United States with South Africa. It is an intercontinental flight between North America and Africa. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 02:36 in Cooperstown, it's 08:36 in Johannesburg. With a 6-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 4,298 feet between the two airports. O. R. Tambo International Airport sits higher than Cooperstown-Westville Airport. Travelers arriving at the higher-elevation airport should be aware of potential altitude effects.

The return flight from Johannesburg (JNB) to Cooperstown (COP) follows a heading of 307° (northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Cooperstown-Westville Airport (COP) and O. R. Tambo International Airport (JNB) detail pages, or use our flight duration calculator to compare other routes.