The flight distance from Tipton Airport (FME) in Fort Meade (Odenton), United States to Rajiv Gandhi International Airport Shamshabad (HYD) in Hyderabad, India is 13,242 kilometers (8,228 miles / 7,150 nautical miles). The estimated flight time for this route is approximately 17h, flying north northeast at a heading of 27°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting United States with India. It is an intercontinental flight between North America and Asia. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 15:51 in Fort Meade (Odenton), it's 02:21 in Hyderabad. With a 10.5-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 1,874 feet between the two airports. Rajiv Gandhi International Airport Shamshabad sits higher than Tipton Airport.

The return flight from Hyderabad (HYD) to Fort Meade (Odenton) (FME) follows a heading of 338° (north northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Tipton Airport (FME) and Rajiv Gandhi International Airport Shamshabad (HYD) detail pages, or use our flight duration calculator to compare other routes.