The flight distance from Lbj Ranch Airport (JCY) in Johnson City, United States to O. R. Tambo International Airport (JNB) in Johannesburg, South Africa is 14,833 kilometers (9,217 miles / 8,009 nautical miles). The estimated flight time for this route is approximately 18h, flying east at a heading of 99°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting United States with South Africa. It is an intercontinental flight between North America and Africa. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 19:13 in Johnson City, it's 03:13 in Johannesburg. With a 8-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 4,043 feet between the two airports. O. R. Tambo International Airport sits higher than Lbj Ranch Airport. Travelers arriving at the higher-elevation airport should be aware of potential altitude effects.

The return flight from Johannesburg (JNB) to Johnson City (JCY) follows a heading of 288° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Lbj Ranch Airport (JCY) and O. R. Tambo International Airport (JNB) detail pages, or use our flight duration calculator to compare other routes.