The flight distance from John F Kennedy International Airport (JFK) in New York, United States to San Cristobal Airport (SCY) in San Cristobal, Ecuador is 4,890 kilometers (3,039 miles / 2,641 nautical miles). The estimated flight time for this route is approximately 7h, flying south southwest at a heading of 203°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting United States with Ecuador. It is an intercontinental flight between North America and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 06:03 in New York, it's 05:03 in San Cristobal.

The return flight from San Cristobal (SCY) to New York (JFK) follows a heading of 17° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and San Cristobal Airport (SCY) detail pages, or use our flight duration calculator to compare other routes.