The flight distance from John F Kennedy International Airport (JFK) in New York, United States to Taisha Airport (TSC) in Taisha, Ecuador is 4,799 kilometers (2,982 miles / 2,591 nautical miles). The estimated flight time for this route is approximately 7h, flying south at a heading of 185°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting United States with Ecuador. It is an intercontinental flight between North America and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 06:02 in New York, it's 06:02 in Taisha.

There is a significant elevation difference of 1,656 feet between the two airports. Taisha Airport sits higher than John F Kennedy International Airport.

The return flight from Taisha (TSC) to New York (JFK) follows a heading of 4° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and Taisha Airport (TSC) detail pages, or use our flight duration calculator to compare other routes.