JFK
New York
United States
1,848 km
1,148 miles
TYM
Staniel Cay Airport
Bahamas
Distance
1,848 km
1,148 mi / 998 nm
Est. Flight Time
3h
Medium-haul route
Time Difference
+0h
America/New_York
Heading
189°
south

Airport Comparison

JFK TYM
Airport Name John F Kennedy International Airport Staniel Cay Airport
IATA Code JFK TYM
ICAO Code KJFK MYES
City New York N/A
Country United States Bahamas
Timezone America/New_York America/Nassau
Elevation 13 ft 5 ft
Coordinates 40.640000, -73.780000 24.170000, -76.440000

New York (JFK) to Staniel Cay Airport (TYM) Flight Distance

The flight distance from John F Kennedy International Airport (JFK) in New York, United States to Staniel Cay Airport (TYM) in Staniel Cay Airport, Bahamas is 1,848 kilometers (1,148 miles / 998 nautical miles). The estimated flight time for this route is approximately 3h, flying south at a heading of 189°.

This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.

This is an international route connecting United States with Bahamas. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 16:41 in New York, it's 16:41 in Staniel Cay Airport.

The return flight from Staniel Cay Airport (TYM) to New York (JFK) follows a heading of 7° (north). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and Staniel Cay Airport (TYM) detail pages, or use our flight duration calculator to compare other routes.

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