The flight distance from John F Kennedy International Airport (JFK) in New York, United States to Major Brigadeiro Trompowsky Airport (VAG) in Varginha, Brazil is 7,514 kilometers (4,669 miles / 4,057 nautical miles). The estimated flight time for this route is approximately 10h, flying south southeast at a heading of 152°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting United States with Brazil. It is an intercontinental flight between North America and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 04:29 in New York, it's 06:29 in Varginha.

There is a significant elevation difference of 3,012 feet between the two airports. Major Brigadeiro Trompowsky Airport sits higher than John F Kennedy International Airport.

The return flight from Varginha (VAG) to New York (JFK) follows a heading of 337° (north northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and Major Brigadeiro Trompowsky Airport (VAG) detail pages, or use our flight duration calculator to compare other routes.