The flight distance from John F Kennedy International Airport (JFK) in New York, United States to Comayagua-Palmerola International Airport (XPL) in Comayagua, Honduras is 3,214 kilometers (1,997 miles / 1,735 nautical miles). The estimated flight time for this route is approximately 5h, flying south southwest at a heading of 209°.

This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.

This is an international route connecting United States with Honduras. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 06:09 in New York, it's 05:09 in Comayagua.

There is a significant elevation difference of 2,051 feet between the two airports. Comayagua-Palmerola International Airport sits higher than John F Kennedy International Airport.

The return flight from Comayagua (XPL) to New York (JFK) follows a heading of 22° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the John F Kennedy International Airport (JFK) and Comayagua-Palmerola International Airport (XPL) detail pages, or use our flight duration calculator to compare other routes.