The flight distance from O. R. Tambo International Airport (JNB) in Johannesburg, South Africa to Staniel Cay Airport (TYM) in Staniel Cay Airport, Bahamas is 12,545 kilometers (7,795 miles / 6,774 nautical miles). The estimated flight time for this route is approximately 16h, flying west northwest at a heading of 287°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting South Africa with Bahamas. It is an intercontinental flight between Africa and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 01:46 in Johannesburg, it's 19:46 in Staniel Cay Airport. With a 6-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

There is a significant elevation difference of 5,553 feet between the two airports. Staniel Cay Airport sits lower than O. R. Tambo International Airport. Travelers arriving at the higher-elevation airport should be aware of potential altitude effects.

The return flight from Staniel Cay Airport (TYM) to Johannesburg (JNB) follows a heading of 110° (east southeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the O. R. Tambo International Airport (JNB) and Staniel Cay Airport (TYM) detail pages, or use our flight duration calculator to compare other routes.