MCO
Orlando
United States
3,381 km
2,101 miles
SCY
San Cristobal
Ecuador
Distance
3,381 km
2,101 mi / 1,825 nm
Est. Flight Time
5h
Medium-haul route
Time Difference
-1h
America/New_York
Heading
197°
south southwest

Airport Comparison

MCO SCY
Airport Name Orlando International Airport San Cristobal Airport
IATA Code MCO SCY
ICAO Code KMCO SEST
City Orlando San Cristobal
Country United States Ecuador
Timezone America/New_York Pacific/Galapagos
Elevation 96 ft 62 ft
Coordinates 28.430000, -81.310000 -0.910000, -89.620000

Orlando (MCO) to San Cristobal (SCY) Flight Distance

The flight distance from Orlando International Airport (MCO) in Orlando, United States to San Cristobal Airport (SCY) in San Cristobal, Ecuador is 3,381 kilometers (2,101 miles / 1,825 nautical miles). The estimated flight time for this route is approximately 5h, flying south southwest at a heading of 197°.

This is a medium-haul route that may be operated by either narrow-body or wide-body aircraft depending on demand. Passengers can expect a meal service on most carriers.

This is an international route connecting United States with Ecuador. It is an intercontinental flight between North America and South America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 06:03 in Orlando, it's 05:03 in San Cristobal.

The return flight from San Cristobal (SCY) to Orlando (MCO) follows a heading of 15° (north northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Orlando International Airport (MCO) and San Cristobal Airport (SCY) detail pages, or use our flight duration calculator to compare other routes.

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