The flight distance from Sir Seewoosagur Ramgoolam International Airport (MRU) in Port Louis, Mauritius to Sandy Lake Airport (ZSJ) in Sandy Lake, Canada is 15,623 kilometers (9,708 miles / 8,436 nautical miles). The estimated flight time for this route is approximately 19h, flying north northwest at a heading of 333°.

This is an ultra-long-haul route, one of the longest in aviation. It requires wide-body aircraft with extended range capability such as the Airbus A350-900ULR or Boeing 777-200LR. Passengers should prepare for an extended flight with multiple meal services.

This is an international route connecting Mauritius with Canada. It is an intercontinental flight between Africa and North America. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 15:12 in Port Louis, it's 05:12 in Sandy Lake. With a 10-hour time difference, travelers should plan for significant jet lag. It typically takes one day per hour of time difference to fully adjust.

The return flight from Sandy Lake (ZSJ) to Port Louis (MRU) follows a heading of 46° (northeast). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Sir Seewoosagur Ramgoolam International Airport (MRU) and Sandy Lake Airport (ZSJ) detail pages, or use our flight duration calculator to compare other routes.