SEG
Selinsgrove
United States
5,759 km
3,578 miles
STN
London
United Kingdom
Distance
5,759 km
3,578 mi / 3,109 nm
Est. Flight Time
8h
Long-haul route
Time Difference
+5h
America/New_York
Heading
50°
northeast

Airport Comparison

SEG STN
Airport Name Penn Valley Airport London Stansted Airport
IATA Code SEG STN
ICAO Code KSEG EGSS
City Selinsgrove London
Country United States United Kingdom
Timezone America/New_York Europe/London
Elevation 464 ft 348 ft
Coordinates 40.820000, -76.860000 51.880000, 0.240000

Selinsgrove (SEG) to London (STN) Flight Distance

The flight distance from Penn Valley Airport (SEG) in Selinsgrove, United States to London Stansted Airport (STN) in London, United Kingdom is 5,759 kilometers (3,578 miles / 3,109 nautical miles). The estimated flight time for this route is approximately 8h, flying northeast at a heading of 50°.

This is a long-haul route typically operated by wide-body aircraft such as the Boeing 777 or Airbus A350. Full meal service, in-flight entertainment, and comfort amenities are standard.

This is an international route connecting United States with United Kingdom. It is an intercontinental flight between North America and Europe. Travelers should check visa requirements, customs regulations, and any travel advisories before booking.

Time zone information: When it's 06:22 in Selinsgrove, it's 11:22 in London. The 5-hour time difference may cause some jet lag. Most travelers adjust within a day or two.

The return flight from London (STN) to Selinsgrove (SEG) follows a heading of 290° (west northwest). Actual flight times may vary depending on wind conditions, air traffic, and the specific aircraft used.

For more information about these airports, visit the Penn Valley Airport (SEG) and London Stansted Airport (STN) detail pages, or use our flight duration calculator to compare other routes.

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